Recaman's Sequence
Time Limit: 3000MS | Memory Limit: 60000K | |
Total Submissions: 18575 | Accepted: 7751 |
Description
The Recaman's sequence is defined by a0 = 0 ; for m > 0, a m = a m−1 − m if the rsulting a m is positive and not already in the sequence, otherwise a m = a m−1 + m. The first few numbers in the Recaman's Sequence is 0, 1, 3, 6, 2, 7, 13, 20, 12, 21, 11, 22, 10, 23, 9 ... Given k, your task is to calculate a k.
Input
The input consists of several test cases. Each line of the input contains an integer k where 0 <= k <= 500000. The last line contains an integer −1, which should not be processed.
Output
For each k given in the input, print one line containing a k to the output.
Sample Input
710000-1
Sample Output
2018658
#include#include const int N=500010;int ch[N];bool vis[N*10];//状态数组一定要开得比数字数组大,否则测试时会RE void init(){ int i,j; memset(vis,false,sizeof(vis)); memset(ch,0,sizeof(ch)); vis[0]=vis[1]=vis[3]=true; ch[0]=0;ch[1]=1; for(i=2;i